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25x-2.5x^2=60
We move all terms to the left:
25x-2.5x^2-(60)=0
a = -2.5; b = 25; c = -60;
Δ = b2-4ac
Δ = 252-4·(-2.5)·(-60)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*-2.5}=\frac{-30}{-5} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*-2.5}=\frac{-20}{-5} =+4 $
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